In parallelogram PQRS, PQ=12 cm and PS=9cm. The bisector of angle P meets SR in M. Both PM and QR meet at T when produced. What is the length of RT? -
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SOLVED:κ=(1)/(3) √((8 R T)/(πM)) (1)/(√(2) πd^2 n) m n (R (l)/(2))/(M)=(R^3 / 2 i T^3 / 2)/(3 π^3 / 2 d^2 √(M) NA) Then from the previous problem q=(2 i R^3 /
![SOLVED:p=(R T)/(V-b)-(a)/(V^2)-V((∂p)/(∂V))T=(R T V)/((V-b)^2)-(2 a)/(V^2) or, κ=(-1)/(V)((∂V)/(∂p))T =[(R T V^3-2 a(V-b)^2)/(V^2(V-b)^2)]^-1=(V^2(V-b))/([R T V^3-2 a(V-b)^2])](https://cdn.numerade.com/previews/cfedf5f8-0a9f-4ae7-8d85-b1655c0d7c70_large.jpg "SOLVED:p=(R T)/(V-b)-(a)/(V^2)-V((∂p)/(∂V))T=(R T V)/((V-b)^2)-(2 a)/(V^2) or, κ=(-1)/(V)((∂V)/(∂p))T =[(R T V^3-2 a(V-b)^2)/(V^2(V-b)^2)]^-1=(V^2(V-b))/([R T V^3-2 a(V-b)^2])")
SOLVED:p=(R T)/(V-b)-(a)/(V^2)-V((∂p)/(∂V))T=(R T V)/((V-b)^2)-(2 a)/(V^2) or, κ=(-1)/(V)((∂V)/(∂p))T =[(R T V^3-2 a(V-b)^2)/(V^2(V-b)^2)]^-1=(V^2(V-b))/([R T V^3-2 a(V-b)^2])
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![PDF] Connectivity properties of the adjacency graph of SLE$_\kappa$ bubbles for $\kappa \in (4,8)$ | Semantic Scholar](https://d3i71xaburhd42.cloudfront.net/3c06419078f9455e0a25bce5bc08fa242a7b54e1/5-Figure2-1.png "PDF] Connectivity properties of the adjacency graph of SLE$_\kappa$ bubbles for $\kappa \in (4,8)$ | Semantic Scholar")
PDF] Connectivity properties of the adjacency graph of SLE$_\kappa$ bubbles for $\kappa \in (4,8)$ | Semantic Scholar
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SOLVED:Use the alternative curvature formula κ=(|𝐯 ×𝐚|)/(|𝐯|^3) to find the curvature of the following parameterized curves. r(t)=(4+t^2, t, 0)
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SOLVED:Find the unit tangent vector 𝐓 and the curvature κfor the following parameterized curves. 𝐫(t)=⟨cos^3 t, sin^3 t⟩
![Association between clinical oral health status and perceived oral health in different age groups [PeerJ]](https://dfzljdn9uc3pi.cloudfront.net/2022/14152/1/fig-1-full.png "Association between clinical oral health status and perceived oral health in different age groups [PeerJ]")
Association between clinical oral health status and perceived oral health in different age groups [PeerJ]
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